MLB Player Danny Jansen Becomes the First to Ever Play for Two Teams in Same Game
After the Blue Jays-Red Sox game was suspended in June, the Toronto catcher was traded to Boston
Lachlan Cunningham/Getty; Brian Fluharty/Getty
Danny Jansen caught one for the history books on Monday.
The Boston Red Sox catcher, 29, became the first player in Major League Baseball history to appear in the same game for two separate teams.
The unlikely quirk of a stat happened because the two teams were finishing out a game from June that was suspended due to rain.
When the original game was rained out in the second inning on June 26, Jansen was actually at bat — and playing for the Blue Jays.
Fast forward exactly two months later, and the Wisconsin native is now the Red Sox catcher, because the team that drafted him in 2013 sent him packing for prospects in a trade last month.
On Monday, Aug. 26, the suspended game — the first in an essentially unplanned double-header — began with the Jays’ Daulton Varsho pinch-hitting in Jansen’s place.
Social media had fun marking the milestone moment.
“Long at-bat, huh,” the Toronto Blue Jays posted on X, alongside a split-screen image of Jansen batting in the June game and Jansen catching the same at-bat in Monday’s matchup.
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Meanwhile MLB posted another side-by-side image of the baseball player and joked: “You win some, you lose some. Just ask Danny Jansen.”
The Red Sox went on to lose both games, 4-1 and 7-3, but for Jansen, the experience was still memorable.
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"Leaving a stamp like that on the game, it’s strange and it’s interesting," Jansen told reporters. "I’m grateful for the opportunity to have that. And at the end of the day, it’s a cool thing.”
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